7x+6^2-(5-2x)+2x^2+1=-3x^2+4-(5x*2-2)+6x

Solution for 7x+6^2-(5-2x)+2x^2+1=-3x^2+4-(5x*2-2)+6x equation:

7x+6^2-(5-2x)+2x^2+1=-3x^2+4-(5x*2-2)+6x

We move all terms to the left:

7x+6^2-(5-2x)+2x^2+1-(-3x^2+4-(5x*2-2)+6x)=0

We add all the numbers together, and all the variables

2x^2-(-3x^2+4-(5x*2-2)+6x)+7x-(-2x+5)+1+6^2=0

We add all the numbers together, and all the variables

2x^2-(-3x^2+4-(5x*2-2)+6x)+7x-(-2x+5)+37=0

We get rid of parentheses

2x^2-(-3x^2+4-(5x*2-2)+6x)+7x+2x-5+37=0


We calculate terms in parentheses: -(-3x^2+4-(5x*2-2)+6x), so:

-3x^2+4-(5x*2-2)+6x

determiningTheFunctionDomain
-3x^2-(5x*2-2)+6x+4

We add all the numbers together, and all the variables

-3x^2+6x-(5x*2-2)+4

We get rid of parentheses

-3x^2+6x-5x*2+2+4

We add all the numbers together, and all the variables

-3x^2+6x-5x*2+6

Wy multiply elements

-3x^2+6x-10x+6

We add all the numbers together, and all the variables

-3x^2-4x+6

Back to the equation:

-(-3x^2-4x+6)


We add all the numbers together, and all the variables

2x^2-(-3x^2-4x+6)+9x+32=0

We get rid of parentheses

2x^2+3x^2+4x+9x-6+32=0

We add all the numbers together, and all the variables

5x^2+13x+26=0

a = 5; b = 13; c = +26;
Δ = b2-4ac
Δ = 132-4·5·26
Δ = -351
Delta is less than zero, so there is no solution for the equation